If the units of force,energy,and velocity are | vedclass

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(B) The dimensional formulas are:Force $F = [MLT^{-2}] = 10\, N \dots (i)$Energy $E = [ML^2T^{-2}] = 100\, J \dots (ii)$Velocity $v = [LT^{-1}] = 5\,

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$10\, m, 4\, kg, 2\, s$

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(B) The dimensional formulas are:Force $F = [MLT^{-2}] = 10\, N \dots (i)$Energy $E = [ML^2T^{-2}] = 100\, J \dots (ii)$Velocity $v = [LT^{-1}] = 5\, m/s \dots (iii)$Dividing equation $(ii)$ by equation $(i)$:$\frac{[ML^2T^{-2}]}{[MLT^{-2}]} = \frac{100\, J}{10\, N} \implies [L] = 10\, m$Substituting $[L] = 10\, m$ into equation $(iii)$:$10\, m / [T] = 5\, m/s \implies [T] = \frac{10\, m}{5\, m/s} = 2\, s$Substituting $[L] = 10\, m$ and $[T] = 2\, s$ into equation $(i)$:$[M][10\, m][2\, s]^{-2} = 10\, N$$[M][10\, m][0.25\, s^{-2}] = 10\, kg\cdot m/s^2$$[M] = \frac{10}{2.5} = 4\, kg$Thus,the units are length $= 10\, m$,mass $= 4\, kg$,and time $= 2\, s$.

If the units of force,energy,and velocity are respectively $10\, N$,$100\, J$,and $5\, m/s$,then the units of length,mass,and time will be:

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